Math Equations

  1. Daisy had 5 apples. She gave 2 to David, leaving her with 3 apples.
  2. The size of the moon is approximately 3,474.8 kilometers in diameter.
  3. My receding hairline… well, I don’t have one! Lucky me!
  4. The size of the Sun is approximately 1,391,000 kilometers in diameter before World War II.

putting it all together:
(3474.8km)×(0/0)+(1,391,000km−3+2)

0/0 form, Inderminant form, Thus answer is NaN

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Not able to solve after this, It would result in e^x/x again, also in the second time of u.v, we’ll get e^x-x^2, any idea how to solve further would be appriciated

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Here’s another math equation then

if the yes is the no, and the yes is the yes, but no is the yes, and yes and no, yes or no and or, yes and and yes yses yse yse no, then what is the yes and the no if the yes is no or yes and no?

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Uhhhhh… chicken nuggets are tasty?

5 - 2 = 3
We don’t need to calculate the size of the moon or my hairline because when you divide by 0, you get undefined.
To add with subtraction, you subtract with adding, and to add with subtraction, you subtract with adding, and to add with subtraction, you- wait…

undefined times the size of the Sun is still undefined

The answer is French fries undefined!

Edit: Do bald people have an infinite hairline or no hairline?

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3x=8-2
x=6/3
x=2

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4x^2 + 2 = 6

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no hairline

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Pythagorean Theorem

a2 + b2 = c2
c = √c2
Alternative:
c = √a2 + b2


Division Algorithm

f(x) ÷ d(x) = q(x) + (r(x) ÷ d(x))


Binomial Distribution

Px = (nx)pxqn - x


Normal Distribution

f(x) = (1 ÷ σ√2π)e-0.5((x - μ) ÷ σ)2


Cubic Equation

ax3 + bx2 + cx + d = 0
Equation for the solutions:


Lagrangian Standard Model


(not math but oh well)

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make a math equation for the answer for the release date of gta 6

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Easy. n x e x v x e x r. Don’t simplify it[1] and you get never.


  1. Or it’ll be n(e2)vr ↩︎

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oh

glo

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images
ive been getting into math geometry recently. lets see if anyone can do this one

find the area of the inscribed square thats tangent to all 4 circles. the square that the circles are inscribed in has a side length of 2

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probably the most roundabout way to solve this lmao

(Edit the graph to see my work)
Feel free to change the square size too

link: “soly | Desmos

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\approx 0.17157

Just for fun, you can do this without trigonometry by using intersections of lines: find the equations for three of the four tangent lines. Two of the lines will be parallel, while the third will be perpendicular to the first two. Find the two points at which the third line intersects with the first two, then calculate the distance between the two points.

Drag the blue dot around to change the origin, drag the green dot around to change the size

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interesting. ive never used desmos so this is a bit confusing. i believe i got that when i did it

btw out of curiosity r u guys able to give an absolute answer (idk what the term is) basically an answer thats not rounded. (i know what it is but im wondering if you guys can write the absolute value of the area of the red square)

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no

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I understant all things (trust

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I think you’re talking about leaving it in radicals, which equals 3-2\sqrt{2} or 3-\sqrt{8}.

(also why do the circles make the square look warped xD)

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I don’t think there’s standard term for this. WolframAlpha calls it exact form(as opposed to approximate form)

The answer is 3 − 2 \cdot \sqrt{2}

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interesting.

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