Glasia AMA 👨🏿‍🦱

Not Terraria Related
1

Ask me anything EXCEPT personal or NSFW questions

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2

If you were to delete a dimension, what would it be? (on DG)

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3

I’d delete PVP.

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4

Would you like to delete the survival dimension because it sucks?

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5

Yes, due to the MS DOS 1.0 anti cheat. You could enable /i in survival and there would be less problems some persons feel.

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6

What is your favourite type of potato?

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7

where did your name glasia come from (for your oc)

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8

Trying to find an interesting Dutch name with G

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9

Just delete everything at this point

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10

Congratulations! You have been promoted to Member!

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11

What is day to day life like in Germany?

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12

u like waffle?

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13

Can you solve this maths question?

Maths Question

Screenshot_20230301-231820_kindlephoto-182167872
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I was gonna write it out but couldnt be bothered so here is a picture of it on a document

I shall post the answer here at some point in the future

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14

So for me theschool life is like: i wake up at 6 AM and then I eat breakfast at home. I prepare my school stuff and then half hour before lesson start I walk the 1.1 mile to school. On the way to school I look via an app on our substitute plan. In German HS if the teacher is absent the lesson is not subbed. If my timetable somehow has a hole of 90 minutes or more, I go back home during that hole. I eat sandwiches while at school. After school I eat soup and for dinner it varies. Right before dinner I shower.

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15

Yes, I like waffles.

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16

  1. Forming the circle formula to the form (x-xc)2 + (y-yc)2 = r2:
    x2-8x+16 + y2-6y+9 -16-9-15=0 <=> (x-4)2+(y-3)2=40.

  2. Expressing the circle with the 2 equations of the semicircles:
    (x-4)2+(y-3)2=40 <=> (y-3)2 = 40-(x-4)2 <=> y-3 = +/- sqrt(40-(x-4)2) <=> y = 3 +/- sqrt(40-(x-4)2. Let cupper(x) = 3 + sqrt(40-(x-4)2) and clower(x) = 3 - sqrt(40-(x-4)2).

  3. Checking on which of the two semicircles P is on:
    Inserting x=-2 to cupper(x) brings: cupper(-2) = 3 + sqrt(40-(-6)2) = 3 + sqrt(40-36) = 3 + sqrt(4) = 3 + 2 = 5 != 1.
    Inserting x=-2 to clower(x) brings: clower(-2) = 3 - sqrt(40-(-6)2) = 3 - sqrt(40-36) = 3 - sqrt(4) = 3 - 2 = 1 = 1.
    Because P is at x=-2 and at y=1 the point P is on clower(x).

  4. Finding the derivative function of clower(x):
    c’lower(x) = d/dx [3 - sqrt(40-(x-4)2)] = - d/dx [sqrt(40-(x-4)2)] = - (d/dx [40-(x-4)2])/(2sqrt(40-(x-4)2)) = d/dx[(x-4)2]/2sqrt(40-(x-4)2) = 2(x-4)/2sqrt(40-(x-4)2) = (x-4)/sqrt(40-(x-4)2).

  5. Finding the value of c’lower(x) at x=-2:
    Insert x=-2 then the slope of the tangent t(x) is m = c’lower(-2) = -6/sqrt(40-(-6)2) = -6/sqrt(40-36) = -6/sqrt(4) = -6/2 = -3.

  6. Finding the tangent equation
    The tangent t has the slope m = -3 and goes through P (-2, 1).
    The equation is after putting x = -2, y = 1 and m = -3 into y=mx+b:
    1 = -3 × (-2) + b <=> 1 = 6+b <=> b = -5.

  7. Answer: Thus the tangent equation is: t(x) = -3x -5.

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17

Solve the quardratic equation: 2*sqrt2x^2+2x+10=30sqrt2

Here is an easy example for x^2+16=25

  1. x^2+16-16=25-16
  2. x^2=9
  3. x=3 (or -3)
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18

Which of these 2 you mean?

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20230302_070428
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19

the first one

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20

Well done you have answered the question correctly
You have done it with much more working than i would have used but that doesn’t really matter
:smile:

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