Glasia AMA 👨🏿‍🦱

[GlasiaVD23 (Glasia)]

Ask me anything EXCEPT personal or NSFW questions

[pwrwq]

If you were to delete a dimension, what would it be? (on DG)

[GlasiaVD23 (Glasia)]

I’d delete PVP.

[twofoursixeight]

Would you like to delete the survival dimension because it sucks?

[GlasiaVD23 (Glasia)]

Yes, due to the MS DOS 1.0 anti cheat. You could enable /i in survival and there would be less problems some persons feel.

[Godlybread (Joe)]

What is your favourite type of potato?

[Solysis]

where did your name glasia come from (for your oc)

[GlasiaVD23 (Glasia)]

Trying to find an interesting Dutch name with G

[OkayZo]

Just delete everything at this point

[twofoursixeight]

Congratulations! You have been promoted to Member!

[Solowing_Pixy (Gyaraga ギャラガ)]

What is day to day life like in Germany?

[Error001]

u like waffle?

[Godlybread (Joe)]

Can you solve this maths question?

Maths Question

I was gonna write it out but couldnt be bothered so here is a picture of it on a document

I shall post the answer here at some point in the future

[GlasiaVD23 (Glasia)]

So for me theschool life is like: i wake up at 6 AM and then I eat breakfast at home. I prepare my school stuff and then half hour before lesson start I walk the 1.1 mile to school. On the way to school I look via an app on our substitute plan. In German HS if the teacher is absent the lesson is not subbed. If my timetable somehow has a hole of 90 minutes or more, I go back home during that hole. I eat sandwiches while at school. After school I eat soup and for dinner it varies. Right before dinner I shower.

[GlasiaVD23 (Glasia)]

Yes, I like waffles.

[GlasiaVD23 (Glasia)]

1. Forming the circle formula to the form (x-x_c)² + (y-y_c)² = r²:
   x²-8x+16 + y²-6y+9 -16-9-15=0 <=> (x-4)²+(y-3)²=40.

2. Expressing the circle with the 2 equations of the semicircles:
   (x-4)²+(y-3)²=40 <=> (y-3)² = 40-(x-4)² <=> y-3 = +/- sqrt(40-(x-4)²) <=> y = 3 +/- sqrt(40-(x-4)². Let c_upper(x) = 3 + sqrt(40-(x-4)²) and c_lower(x) = 3 - sqrt(40-(x-4)²).

3. Checking on which of the two semicircles P is on:
   Inserting x=-2 to c_upper(x) brings: c_upper(-2) = 3 + sqrt(40-(-6)²) = 3 + sqrt(40-36) = 3 + sqrt(4) = 3 + 2 = 5 != 1.
   Inserting x=-2 to c_lower(x) brings: c_lower(-2) = 3 - sqrt(40-(-6)²) = 3 - sqrt(40-36) = 3 - sqrt(4) = 3 - 2 = 1 = 1.
   Because P is at x=-2 and at y=1 the point P is on c_lower(x).

4. Finding the derivative function of c_lower(x):
   c’_lower(x) = d/dx [3 - sqrt(40-(x-4)²)] = - d/dx [sqrt(40-(x-4)²)] = - (d/dx [40-(x-4)²])/(2sqrt(40-(x-4)²)) = d/dx[(x-4)²]/2sqrt(40-(x-4)²) = 2(x-4)/2sqrt(40-(x-4)²) = (x-4)/sqrt(40-(x-4)²).

5. Finding the value of c’_lower(x) at x=-2:
   Insert x=-2 then the slope of the tangent t(x) is m = c’_lower(-2) = -6/sqrt(40-(-6)²) = -6/sqrt(40-36) = -6/sqrt(4) = -6/2 = -3.

6. Finding the tangent equation
   The tangent t has the slope m = -3 and goes through P (-2, 1).
   The equation is after putting x = -2, y = 1 and m = -3 into y=mx+b:
   1 = -3 × (-2) + b <=> 1 = 6+b <=> b = -5.

7. Answer: Thus the tangent equation is: t(x) = -3x -5.

[twofoursixeight]

Solve the quardratic equation: 2*sqrt2x^2+2x+10=30sqrt2

Here is an easy example for x^2+16=25

1. x^2+16-16=25-16
2. x^2=9
3. x=3 (or -3)

[GlasiaVD23 (Glasia)]

Which of these 2 you mean?

[twofoursixeight]

the first one

[Godlybread (Joe)]

Well done you have answered the question correctly
You have done it with much more working than i would have used but that doesn’t really matter